Missing number · noteswale

1. Ye topic hai kya?

Paper ek figure deta hai — 3×3 box, triangle, circle ke tukde — ek jagah ?. Wahi number nikaalo jo baaki cells ke rule se fit ho.

Number series se farq

Series: 4, 9, 19, ?, 79 — ek line, agla/beech. Yeh page figure ka ? hai. Line wala Number Series pe hai.

Figure series se farq

Shapes/mirror mein picture agla/odd. Yahan picture ke andar numbers hain, shape nahi badalti.

2. Paper pe dimag kaise chale

Yahi order (40 second):
1) Grid — pehle row, fail to column, phir diagonal
2) Try: sum, product, a×b ± k, a² ± b, a² + b²
3) Triangle — teen kona + beech. Beech aksar konon ka sum / product / (a+b)×c
4) Circle — opposite jodi same sum, ya A×C − B×D
5) Jo rule saari complete lines pe chale, wahi ? pe lagaao
6) Do rules dono fit hon to simpler wala + options

Galati: ek row pe rule soch ke turant tick. Doosri complete row pe verify. Fail = rule galat.

3. Grid (3×3 box)

Har row (ya column) ek mini-sawaal. Do complete rows se lock, teesri pe ?.

Basic · row sum

Q1. ? kya hai?

2	5	7
4	3	7
6	9	?

Solution shuru

Step 1 — row 1
2 + 5 = 7. Teesra = pehle do ka sum.
Step 2 — row 2
4 + 3 = 7. Wahi rule.
Step 3 — row 3
6 + 9 = 15.

Final answer — yahan khatam15

Basic · product

Q2. ? kya hai?

2	3	6
4	5	20
3	4	?

Solution shuru

Step 1
2 × 3 = 6. 4 × 5 = 20. Product.
Step 2
3 × 4 = 12. Sum hota to 2+3=5 hota, 6 nahi — isliye + nahi.

Final answer — yahan khatam12

Medium · × phir −

Q3. ? kya hai?

3	4	11
5	2	9
6	3	?

Solution shuru

Step 1 — sum/product fail
3+4=7 ≠ 11. 3×4=12, 12−1=11.
Step 2
5×2 − 1 = 9. Lock: a×b − 1.
Step 3
6×3 − 1 = 17.

Final answer — yahan khatam17

4. Triangle

Teen kona (top, left, right) + beech ka number. Beech nikaalo, ya kabhi ek kona.

Basic · kona sum

Q4. Pehle triangle mein centre = teen konon ka sum. Doosre ka centre?

4+5+6=15

8+1+4=?

Solution shuru

Step 1
Pehla: 4+5+6=15. Centre = sum.
Step 2
8+1+4=13.

Final answer — yahan khatam13

Basic · product

Q5. Centre = teen konon ka product. Doosra centre?

2×3×4=24

2×2×5=?

Solution shuru

Step 1
2×3×4=24. Sum 9 hota — centre 24 hai, isliye product.
Step 2
2×2×5=20.

Final answer — yahan khatam20

Medium · (a+b)×c

Q6. Centre = (top + left) × right. Teesra centre?

(3+5)×2=16

(4+2)×3=18

(5+1)×4=?

Solution shuru

Step 1
Sum of three: 3+5+2=10 ≠ 16. Product 30 ≠ 16. Mix chahiye.
Step 2
(3+5)×2=16. Doosre pe (4+2)×3=18. Lock.
Step 3
(5+1)×4=24. (Sirf top×left+right = 5+4=9 — complete figures pe nahi chalta.)

Final answer — yahan khatam24

5. Circle / opposite

Chaar tukde: upar–neeche ek jodi, left–right doosri. Aksar dono jodi ka sum same.

Basic · opposite sum

Q7. Opposite numbers ka sum same. Left wala ??

Solution shuru

Step 1
Upar 8 + neeche 7 = 15.
Step 2
Right 5 + left ? = 15 → ? = 10.

Final answer — yahan khatam10

6. Square mix — a² ± b

Jab sum/product chhote pad jaayein: pehla number square, doosra add/subtract.

Medium · a² + b²

Q8. Teesra number = pehle do ke squares ka sum.

5	6	61
4	3	25
7	2	?

Solution shuru

Step 1
5+6=11 ≠ 61. 5×6=30 ≠ 61. Squares: 25+36=61.
Step 2
16+9=25. Lock.
Step 3
49+4=53.

Final answer — yahan khatam53

Medium · a² − b

Q9. ? kya hai?

5	3	22
6	4	32
7	2	?

Solution shuru

Step 1
5×3+7=22? Forced. Seedha: 5² − 3 = 22.
Step 2
6² − 4 = 32. Lock: a² − b.
Step 3
7² − 2 = 47.

Final answer — yahan khatam47

Pro · A×C − B×D

Q10. Clockwise A, B, C, D. Centre = A×C − B×D. Doosra centre?

5×4 − 2×3 = 14

7×4 − 3×2 =?

Solution shuru

Step 1
Opposite product: 5×4=20, 2×3=6. 20−6=14. Centre match.
Step 2
7×4=28, 3×2=6. 28−6=22.
Step 3 — sum to nahi
5+2+4+3=14 coincidentally pehle figure pe. Doosre 7+3+4+2=16 ≠ koi obvious centre — isliye sum nahi, product-difference hai.

Final answer — yahan khatam22

7. Pro checklist

Do complete units pe rule, teesri pe apply.
Row fail → column. Triangle: sum, product, phir (a+b)×c.
Circle: opposite sum, phir opposite product minus.
Bada teesra number (61, 53) → squares socho.
Ek cell unused reh jaaye to rule kamzor.
Line series (2, 6, 12, ?) is page ka kaam nahi — Number Series pe jaao.

8. Practice

Pehle khud socho, phir neeche solution kholo. Q1–Q10 yahan nahi dohraaye.

Basic

Practice 1. ? kya hai?

1	4	5
2	6	8
3	5	?

Solution shuru

Step 1
1+4=5, 2+6=8, 3+5=8.

Final answer — yahan khatam8

Basic

Practice 2. Rows pe sum nahi chalta. Column try karo.

2	9	4
5	3	8
7	12	?

Solution shuru

Step 1 — row fail
2+9=11 ≠ 4. Product 18 ≠ 4.
Step 2 — column
2+5=7, 9+3=12. Teesra column: 4+8=12.

Final answer — yahan khatam12

Medium

Practice 3. Har row ka sum same.

2	7	6
9	5	1
4	3	?

Solution shuru

Step 1
2+7+6=15. 9+5+1=15.
Step 2
4+3+?=15 → ?=8.

Final answer — yahan khatam8

Basic

Practice 4. Centre = konon ka sum. Doosra centre?

Solution shuru

Step 1
9+6+3=18. 5+7+2=14.

Final answer — yahan khatam14

Basic

Practice 5. Centre = product. Doosra centre?

Solution shuru

Step 1
2×4×3=24. 5×2×2=20.

Final answer — yahan khatam20

Basic

Practice 6. Opposite sum same. Left ??

Solution shuru

Step 1
12+4=16. 9+?=16 → 7.

Final answer — yahan khatam7

Medium

Practice 7. Har row: andar = left² + right.

5	2	27
6	1	37
4	3	?

Solution shuru

Step 1
5² + 2 = 27. 6² + 1 = 37.
Step 2
4² + 3 = 19.

Final answer — yahan khatam19

Medium

Practice 8. Teesra = a×b + b.

3	2	8
4	3	15
5	2	?

Solution shuru

Step 1
3×2 + 2 = 8. (3²=9, chalta nahi — extra cell use ho raha hai.)
Step 2
4×3 + 3 = 15. Lock.
Step 3
5×2 + 2 = 12.

Final answer — yahan khatam12

Medium

Practice 9. Chaar numbers: teen ka sum = chautha. Teesri figure ka ??

2	3	6	11
4	5	1	10
7	2	3	?

Solution shuru

Step 1
2+3+6=11. 4+5+1=10.
Step 2
7+2+3=12.

Final answer — yahan khatam12

Pro

Practice 10. Centre = (top − left) × right.

(8−3)×2=10

(7−2)×4=?

Solution shuru

Step 1
Sum 8+3+2=13 ≠ 10. Product 48 ≠ 10. (8−3)×2=10.
Step 2
(7−2)×4=20.

Final answer — yahan khatam20

9. Itna kaafi hai kya?

Agar grid pe row/column lock, triangle pe sum-product-mix, circle pe opposite, aur bade numbers pe squares chala sako, to JA/CA-II ke figure-missing sawaal basic se pro tak attempt ho sakte hain.

Agle topic: Blood relations.