1. Ye topic hai kya?
Cube ki 6 faces — dice par number/dot, ya rang se paint karke chhote cubes. 2D ulti figure yahan nahi (Shapes / mirror).
Paper kya maangta
Kaun si face opposite, do photos same dice ki, kaun sa net fold hoga, n×n×n kaatne ke baad kitni faces painted.
Pehle lock
Ek view mein teen faces dikhti hain — wo teen ek hi kone par milti hain. Aapas mein koi opposite nahi.
2. Cube — 6, 12, 8
Har face ke 4 padosi (edge se jude) aur 1 opposite (kabhi saath nahi dikhti)
3. Ordinary dice — tabhi 7
Kuch sawaal likhte hain “ordinary / standard dice” ya “opposite faces ka sum 7”.
1 ↔ 6 · 2 ↔ 5 · 3 ↔ 4 4. Do positions — yahi asli method
Same dice, do photos. Figure mein teen faces: saamne / upar / daayan.
Ek common face X → dono photos ki baaki faces X ke padosi. Jo number 1–6 mein dikha hi nahi, wahi X ka opposite.
5. Net — khula cube
6 squares ka pattern jo fold hoke cube bane. Seedha 4 se zyada squares ek line mein = fold nahi hota (5–6 wali strip galat).
3-strip
A–B–C → A opposite C4-strip
A–B–C–D → A opposite C, B opposite D 6. Painted cube, phir n×n×n kaato
Bada cube 6 taraf paint, phir chhote unit cubes. Poora n³.
| Painted faces | Formula | 3×3×3 | 4×4×4 |
|---|---|---|---|
| 3 (konas) | 8 hamesha (n≥2) | 8 | 8 |
| 2 (edges, kona chhod) | 12(n−2) | 12 | 24 |
| 1 (face ke beech) | 6(n−2)² | 6 | 24 |
| 0 (andar) | (n−2)³ | 1 | 8 |
n−2=0. Sirf 8 cubes, sab 3-face painted. 2-face / 1-face / andar = 0. 7. Sawal — basic se pro
Q3–Q4, Q7 ek hi cube pe chalenge: saamne 1, peeche 2, upar 3, neeche 4, daayan 5, baayan 6. Opposite: 1–2, 3–4, 5–6. Ordinary nahi (1+2=3, 7 nahi).
Ek view mein 2, 3, 5 dikh rahe hain (teen kone par milte hain). 2 ka opposite nahi ho sakta?
- 1
- 3
- 4
- 6
Solution
- Step 1
Jo saath dikhe, wo opposite nahi. 2 ke saath 3 aur 5 hain.
- Step 2
3 definitely nahi. 1, 4, 6 abhi possible — itna data unhe kaatne ko kaafi nahi.
Ordinary dice. 2 ke opposite kaun si face?
- 3
- 4
- 5
- 6
Solution
- Step 1
Ordinary = opposite sum 7. 2 + 5 = 7.
Same dice, do positions. 1 ke opposite?
- 3
- 5
- 2
- 6
Solution
- Step 1
I: 1, 3, 5. II: 5, 3, 2. Common do faces: 3 aur 5.
- Step 2
Jo teesri bachi: I mein 1, II mein 2. Do-common rule: 1 opposite 2.
- Step 3
3 aur 5 dono views mein hain — wo 1 ke opposite nahi (padosi).
Wahi dice. Position I wahi (1, 3, 5). Position II neeche. 3 ke opposite?
- 1
- 2
- 4
- 5
Solution
- Step 1
I: 1, 3, 5. II: 2, 3, 6. Common sirf 3.
- Step 2
Dikh numbers: 1, 2, 3, 5, 6. Jo nahi dikha: 4.
- Step 3
Ek-common rule: jo sixth bacha, wahi common ka opposite. 3 ↔ 4. (1 aur 5, 3 ke padosi the — opposite nahi.)
3×3×3 cube, 6 taraf paint, phir 27 chhote. Kitne cubes ki exactly 2 faces painted?
- 6
- 8
- 12
- 27
Solution
- Step 1
2-face = 12 edges × (n−2) = 12 × 1 = 12. (Har edge ke do konas 3-face wale hain, beech wala ek 2-face.)
4×4×4, 6 taraf paint, kaato. Kitne chhote cubes bina paint?
- 1
- 4
- 8
- 16
Solution
- Step 1
Andar wala cube (n−2)³ = 2³ = 8.
- Step 2
Check: kul 64. 3-face 8 + 2-face 24 + 1-face 24 + 0-face 8 = 64.
Yeh net fold hoke cube. 6 ke opposite?
- 1
- 2
- 4
- 5
Solution
- Step 1
Row
6–1–5teen strip: 6 opposite 5. (Beech 1 dono se judi, fold par 6 aur 5 do taraf.) - Step 2
Column
3–1–4–2: 3 opposite 4, 1 opposite 2. 6 ka opposite 1 nahi — 1 padosi hai.
Ordinary dice. 4 neeche hai. Upar kaun si?
- 2
- 3
- 5
- 6
Solution
- Step 1
Neeche-upar opposite. 4 + 3 = 7. Upar = 3.
Kaun sa net cube nahi banata?
Solution
- Step 1
C mein seedhi 5 squares. Cube ki belt 4 faces ki hoti hai — 5-strip fold hoke overlap. Galat net.
- Step 2
A Latin-cross (6) theek. B 2×3 rectangle theek — trap. D plus+ek theek.
Ordinary dice. Kaun sa view impossible?
Solution
- Step 1
Ordinary: 2 ↔ 5, 1 ↔ 6, 3 ↔ 4. Jo pair ek view mein saath aaye, wo galat.
- Step 2
C: 2 aur 5 dono dikh rahe — opposite pair visible. Impossible.
- Step 3
A: 1,2,3 — koi opposite pair nahi, kone par mil sakte. B: 1,3,5 theek. D: 1,2,4 theek (3↔4 isliye 4 padosi hai 1,2 ki).
Practice
Pehle khud, phir neeche kholo.
View mein 1, 4, 6 dikhte hain. 1 ka opposite nahi ho sakta?
- 2
- 3
- 4
- 5
Solution
- Step 1
1 ke saath 4 dikha. Opposite 4 nahi. Baaki options abhi possible.
Ordinary dice. 6 ke opposite?
- 1
- 2
- 3
- 5
Solution
- Step 1
6 + 1 = 7.
Do positions. 6 ke opposite?
- 1
- 3
- 4
- 5
Solution
- Step 1
I: 6,4,1. II: 1,4,3. Common do: 4 aur 1.
- Step 2
Teesri: 6 aur 3. 6 opposite 3.
P3 wala dice. Position I (6, 4, 1) aur yeh II. 4 ke opposite?
- 1
- 2
- 5
- 6
Solution
- Step 1
I: 6,4,1. II: 3,4,2. Common sirf 4. Dikh: 1,2,3,4,6. Bacha 5.
- Step 2
4 opposite 5.
3×3×3, 6 taraf paint. Kitne cubes par paint bilkul nahi?
- 0
- 1
- 6
- 8
Solution
- Step 1
(3−2)³ = 1 — bilkul beech wala.
5×5×5, 6 taraf paint. Exactly 2 faces painted?
- 12
- 24
- 36
- 48
Solution
- Step 1
12(n−2) = 12×3 = 36.
Is net mein 2 ke opposite?
- A
- B
- C
- D
Solution
- Step 1
Column A–2–E: 3-strip, A opposite E — poocha 2 ka nahi.
- Step 2
Row B–2–C–D: 4-strip. B opposite C, 2 opposite D.
Ordinary dice. 1 upar. Neeche?
- 2
- 4
- 5
- 6
Solution
- Step 1
Upar-neeche opposite. 1 ↔ 6.
2×2×2 cube, 6 taraf paint, 8 pieces. Exactly 2 faces painted kitne?
- 0
- 4
- 8
- 12
Solution
- Step 1
n−2=0. 12×0=0. Har chhota cube ek kona hai — 3 faces painted, 2-face koi nahi.
P3–P4 wale dice pe opposite 6–3, 4–5, 1–2. Kaun sa view impossible?
- 6, 4, 1 saath
- 6, 3, 4 saath
- 3, 4, 2 saath
- 6, 4, 2 saath
Solution
- Step 1
B: 6 aur 3 opposite, ek view mein saath — impossible.
- Step 2
A Position I tha. C P4-II tha. D: 6,4,2 — 1↔2 isliye 2 padosi ho sakta 6,4 ka (baayan-neeche-peeche wala kona nahi, lekin 6 ke padosi 4,5,1,2). 4 aur 2 dono 6 ke padosi; 4 ke padosi 6,1,3,2. Teen 6,4,2 milte hain. Theek.
